2018-09-19 11:23:05 +00:00
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# [83. Remove Duplicates from Sorted List](https://leetcode.com/problems/remove-duplicates-from-sorted-list/description/)
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# 思路
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去除链表中的重复元素。
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设置两个相邻的指针pre和p,pre代表已处理部分的最后一个节点,p代表待处理节点,比较pre和p的值来决定是否删除p;
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# C++
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2019-09-13 15:08:41 +00:00
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``` C++
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2018-09-19 11:23:05 +00:00
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/**
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* Definition for singly-linked list.
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* struct ListNode {
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* int val;
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* ListNode *next;
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* ListNode(int x) : val(x), next(NULL) {}
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* };
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*/
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class Solution {
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public:
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ListNode* deleteDuplicates(ListNode* head) {
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if(head == NULL) return head;
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ListNode *pre = head, *p = head -> next, *dup; // dup是待删除的重复节点
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while(p){
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while(p !=NULL && p -> val == pre -> val){ // 若p的值等于pre的值
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pre -> next = p -> next; // 指针跳过p
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dup = p;
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dup -> next = NULL;
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delete dup;
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p = pre -> next; // p指针后移
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}
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pre = p; // pre后移
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if(p) p = p -> next;
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}
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return head;
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}
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};
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```
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