mirror of
https://github.com/ShusenTang/LeetCode.git
synced 2024-09-02 14:20:01 +00:00
43 lines
1.2 KiB
Markdown
43 lines
1.2 KiB
Markdown
![]() |
# [393. UTF-8 Validation](https://leetcode.com/problems/utf-8-validation/)
|
|||
|
# 思路
|
|||
|
|
|||
|
此题让我们验证给定的编码是否是合法的 UTF-8 编码。
|
|||
|
|
|||
|
此题感觉没啥好说的,按照题目进行验证即可,详见代码。
|
|||
|
|
|||
|
**需要注意的是题目给的是【单个字符】的UTF-8规则,而实际却让我们判断的是【字符序列】** 估计这也是为什么那么多人给此题倒赞吧....实属坑题
|
|||
|
|
|||
|
# C++
|
|||
|
``` C++
|
|||
|
class Solution {
|
|||
|
private:
|
|||
|
int pre_1(int n){ // 计算有多少个前导1
|
|||
|
int mask = 128;
|
|||
|
int res = 0;
|
|||
|
while(mask & n){
|
|||
|
res++;
|
|||
|
mask >>= 1;
|
|||
|
}
|
|||
|
return res;
|
|||
|
}
|
|||
|
public:
|
|||
|
bool validUtf8(vector<int>& data) {
|
|||
|
int i = 0;
|
|||
|
# define start_with_10(n) ((n & 0x000000c0) == 128)
|
|||
|
while(i < data.size()){
|
|||
|
int num_pre1 = pre_1(data[i]);
|
|||
|
if(!num_pre1) i++;
|
|||
|
else{
|
|||
|
if(num_pre1 == 1 || num_pre1 > 4) return false;
|
|||
|
for(int j = 1; j < num_pre1; j++){
|
|||
|
if(j + i == data.size() || !start_with_10(data[j+i]))
|
|||
|
return false;
|
|||
|
}
|
|||
|
i += num_pre1;
|
|||
|
}
|
|||
|
}
|
|||
|
return true;
|
|||
|
}
|
|||
|
};
|
|||
|
```
|