Create 455. Assign Cookies.md

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# [455. Assign Cookies](https://leetcode.com/problems/assign-cookies/description/)
# 思路
贪心。从最小饼干开始分配直到无法分配。
先将g和s从小到大排序孩子和饼干分别用下标i和ji和j都从0开始:
* 若g[i] > s[j]即此时的最小饼干j无法满足此时要求最少的孩子i应该尝试下一个饼干j+1
* 若g[i] <= s[j]即此时的最小饼干能满足此时要求最少的孩子i应该将j分配给i。i++以处理下一个孩子j++以处理下一块饼干。
时间复杂度O(n)。
# C++
```
class Solution {
public:
int findContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(), g.end());
sort(s.begin(), s.end());
int i = 0, j = 0, res = 0;
while(i < g.size() && j < s.size()){
while(j < s.size() && g[i] > s[j]) j++;
if(j++ < s.size()) res++;
i++;
}
return res;
}
};
```