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+# [566. Reshape the Matrix](https://leetcode.com/problems/reshape-the-matrix/description/)
+# 思路
+题意就是将一个二维数组按要求reshape成另一个二维数组使得有同样的row-traversing顺序，即按照行优先遍历应该得到同样的结果。   
+用一个count计数，然后对原数组遍历一遍将每个元素填到新数组合适的位置即可。
+# C++
+```
+class Solution {
+public:
+    vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c) {
+        int original_r = nums.size(), original_c = nums[0].size();
+        if( r * c != original_r * original_c) return nums;
+        vector<vector<int>>result;
+        vector<int>one_row;
+        int count = 0;
+        for(int i = 0; i < r; i++){
+            for(int j = 0; j < c; j++){
+                one_row.push_back(nums[count / original_c][count % original_c]);
+                count++;
+            }
+            result.push_back(one_row);
+            one_row.clear();
+        }
+        return result;
+    }
+};
+```