Create 111. Minimum Depth of Binary Tree.md

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# [111. Minimum Depth of Binary Tree](https://leetcode.com/problems/minimum-depth-of-binary-tree/description/)
# 思路
求二叉树的最小深度。依次分为以下情况:
* 若为空树则返回0
* 否则若左右子树都为空返回1
* 否则若左子树为空那么最小深度就为右子树的最小深度加1若右子树为空那么最小深度就为左子树的最小深度加1
* 否则(即左右子树都不空)那么最小深度就是min(1+左子树最小深度, 1+右子树最小深度)
# C++
``` C++
class Solution {
public:
int minDepth(TreeNode* root) {
if(root == NULL) return 0;
else if(root -> left == NULL && root -> right == NULL) return 1;
else if(root -> left == NULL) return 1 + minDepth(root -> right);
else if(root -> right == NULL) return 1 + minDepth(root -> left);
return 1 + min(minDepth(root -> left), minDepth(root -> right));
}
};
```