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95 lines
1.7 KiB
Markdown
95 lines
1.7 KiB
Markdown
# Load
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The `load`/`strload` operator allows you to load in content from another file referenced in your yaml document.
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Note that you can use string operators like `+` and `sub` to modify the value in the yaml file to a path that exists in your system.
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Use `strload` to load text based content as a string block, and `load` to interpret the file as yaml.
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Lets say there is a file `../../examples/thing.yml`:
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```yaml
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a: apple is included
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b: cool
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```
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## Simple example
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Given a sample.yml file of:
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```yaml
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myFile: ../../examples/thing.yml
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```
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then
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```bash
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yq eval 'load(.myFile)' sample.yml
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```
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will output
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```yaml
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a: apple is included
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b: cool.
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```
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## Replace node with referenced file
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Note that you can modify the filename in the load operator if needed.
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Given a sample.yml file of:
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```yaml
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something:
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file: thing.yml
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```
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then
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```bash
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yq eval '.something |= load("../../examples/" + .file)' sample.yml
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```
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will output
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```yaml
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something:
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a: apple is included
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b: cool.
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```
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## Replace _all_ nodes with referenced file
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Recursively match all the nodes (`..`) and then filter the ones that have a 'file' attribute.
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Given a sample.yml file of:
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```yaml
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something:
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file: thing.yml
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over:
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here:
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- file: thing.yml
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```
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then
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```bash
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yq eval '(.. | select(has("file"))) |= load("../../examples/" + .file)' sample.yml
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```
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will output
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```yaml
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something:
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a: apple is included
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b: cool.
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over:
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here:
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- a: apple is included
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b: cool.
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```
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## Replace node with referenced file as string
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This will work for any text based file
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Given a sample.yml file of:
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```yaml
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something:
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file: thing.yml
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```
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then
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```bash
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yq eval '.something |= strload("../../examples/" + .file)' sample.yml
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```
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will output
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```yaml
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something: |-
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a: apple is included
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b: cool.
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```
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