Create 110. Balanced Binary Tree.md

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# [110. Balanced Binary Tree](https://leetcode.com/problems/balanced-binary-tree/description/)
# 思路
一棵非空树是平衡二叉树的充要条件是:
* 其左右子树的高相差不超过1
* 且左右子树都是平衡二叉树。
因此是一个递归算法。
# C++
``` C++
class Solution {
private:
int getDepth(TreeNode *root){
if(root == NULL) return 0;
return 1 + max(getDepth(root -> left), getDepth(root -> right));
}
public:
bool isBalanced(TreeNode* root) {
if(root == NULL) return true;
return (abs(getDepth(root -> left) - getDepth(root -> right)) <= 1) && isBalanced(root -> left) && isBalanced(root -> right);
}
};
```