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22 lines
727 B
Markdown
22 lines
727 B
Markdown
# [434. Number of Segments in a String](https://leetcode.com/problems/number-of-segments-in-a-string/description/)
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# 思路
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计算一个字符串被空格分成了多少部分。
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从头至尾遍历字符串,用tag标记当前字符的前一个字符是否是空格,若tag=1则前面是空格否则不是。若当前字符不是空格且tag==1则count应该加1。
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# C++
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```C++
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class Solution {
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public:
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int countSegments(string s) {
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int tag = 1, res = 0;
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for(int p = 0; p < s.size(); p++){
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if(s[p] == ' ') tag = 1;
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else if(tag == 1){ // 当前字符不是空格且tag==1
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res++;
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tag = 0;
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}
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}
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return res;
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}
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};
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```
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